## Intermediate Algebra for College Students (7th Edition)

The answer is $\left[\begin{array}{ccc|c} 1 & -3 & 2&5 \\ 1 &5 &-5&0 \\ 3&0&4&7\\ \end{array}\right]$.
The given matrix is The given matrix is $\left[\begin{array}{ccc|c} 2 & -6 & 4&10 \\ 1 &5 &-5&0 \\ 3&0&4&7\\ \end{array}\right]$ Perform $\frac{1}{2}R_1$. Multiply row 1 by $\frac{1}{2}$. $\left[\begin{array}{ccc|c} 2\cdot \frac{1}{2} & -6\cdot \frac{1}{2} & 4\cdot \frac{1}{2}&10\cdot \frac{1}{2} \\ 1 &5 &-5&0 \\ 3&0&4&7\\ \end{array}\right]$ Simplify. $\left[\begin{array}{ccc|c} 1 & -3 & 2&5 \\ 1 &5 &-5&0 \\ 3&0&4&7\\ \end{array}\right]$