Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 3 - Section 3.4 - Matrix Solutions to Linear Systems - Exercise Set - Page 228: 5

Answer

The answer is $\left(\begin{array}{cc|c} 1 & -3 & 5 \\ 0 & 12 &-6 \\ \end{array}\right)$.

Work Step by Step

The given matrix is $\left(\begin{array}{cc|c} 1 & -3 & 5 \\ 2 & 6 & 4 \\ \end{array}\right)$. Perform $ -2R_2+R_2 $. Multiply row 2 by $-2 $ and add to the row 2 as shown below. $\left(\begin{array}{cc|c} 1 & -3 & 5 \\ -2\cdot 1+2 & -2\cdot (-3) +6 &-2\cdot 5+ 4 \\ \end{array}\right)$ Simplify. $\left(\begin{array}{cc|c} 1 & -3 & 5 \\ -2+2 & 6+6 &-10+ 4 \\ \end{array}\right)$ $\left(\begin{array}{cc|c} 1 & -3 & 5 \\ 0 & 12 &-6 \\ \end{array}\right)$.
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