Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 3 - Section 3.2 - Problem Solving and Business Applications Using Systems of Equations - Exercise Set - Page 207: 44



Work Step by Step

Here, $C(x)=10,000+3x; R(x)=50x$ when the revenue breaks with the costs then $C(x)=R(x)$ Thus, $10,000+3x=50x$ or, $10,000=50-30x$ or, $x=500$ Amount of profit function $P(x)=R(x)-C(x)$ or, $=50x-(10,000+3x)$ Thus, $P(x)=20x-10,000$ Now, $P(300)=20(300)-10,000$ or, $P(300)=-4000$
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