Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 3 - Section 3.1 - Systems of Linear Equations in Two Variables - Exercise Set - Page 193: 98

Answer

(a.) Sold $ = 6550 $, Supply $ = 6250$. (b.) Ticket price $ =\$ 60 $, Tickets supplied and sold $ = 6300 $.

Work Step by Step

Demand model $ N=-25p+7800 $ ... (1). Supply model $ N=5p+6000 $ ... (2). Where, $ p= $ dollars per ticket and $N$ is number of tickets. (a.) Substitute $ p=\$ 50 $ in equation (1) and (2). Demand model :- $ N=-25(50)+7800 $ $ N= -1250+7800 $ $ N= 6550 $ Supply model :- $ N=5(50)+6000 $ $ N=250+6000 $ $ N=6250 $ Hence, at $ \$ 50 $ per ticket, $ 6550 $ tickets can be sold and $ 6250 $ tickets can be supplied. (b.) Equate equation (1) and (2). $ -25p+7800 =5p+6000 $ $ 7800 - 6000 = 5p+25p $ $ 1800 = 30p $ $ 60 = p $ Substitute the above value into equation (1). $ N=-25(60)+7800 $ $ N= -1500+7800$ $ N =6300 $.
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