## Intermediate Algebra for College Students (7th Edition)

When solving $3x-2y=5$ and $y=3x-3$ by the substitution method, we obtain $x=\frac{1}{3}$, so the solution set is ${(\frac{1}{3},-2)}$.
When solving $3x-2y=5$ and $y=3x-3$ by the substitution method, we obtain $x=\frac{1}{3}$, so the solution set is ${(\frac{1}{3},-2)}$.