Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 3 - Cumulative Review Exercises - Page 251: 12

Answer

The graph is shown below.

Work Step by Step

The given equation of the line is $\Rightarrow 2x-y=6$ Plug $y=0$ for the $x−$intercept. $\Rightarrow 2x-0=6$ Divide both sides by $2$. $\Rightarrow x=3$ The $x−$intercept is $3$, so the line passes through $(3,0)$. Plug $x=0$ for the $y−$intercept. $\Rightarrow 2(0)-y=6$ Simplify. $\Rightarrow -y=6$ Multiply both sides by $-1$. $\Rightarrow y=-6$ The $y−$intercept is $-6$, so the line passes through $(0,-6)$. Checkpoint plug $y=2$. $\Rightarrow 2x-2=6$ Add $2$ to both sides. $\Rightarrow 2x-2+2=6+2$ $\Rightarrow 2x=8$ Divide both sides by $2$. $\Rightarrow x=4$ The checkpoint is $(4,2)$. Draw a straight line through these three points.
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