## Intermediate Algebra for College Students (7th Edition)

(a.) Hence, the point $(-5,-6)$ satisfy $2x-y=-4$. (b.) Hence, the point $(-5,-6)$ satisfy $3x-5y=15$
(a.) The given point is $(-5,-6)$ and the equation is $2x-y=-4$. Substitute $x=-5$ and $y=-6$ into the equation. $2(-5)-(-6)=-4$ $-10+6=-4$ $-4 = -4$. Satisfied. (b.) The given point is $(-5,-6)$ and the equation is $3x-5y=15$. Substitute $x=-5$ and $y=-6$ into the equation. $3(-5)-5(-6)=15$ $-15+30=15$ $15 = 15$. Satisfied.