Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 2 - Section 2.5 - The Point-Slope Form of the Equation of a Line - Exercise Set - Page 167: 98

Answer

(a.) Hence, the point $ (-5,-6) $ satisfy $ 2x-y=-4 $. (b.) Hence, the point $ (-5,-6) $ satisfy $ 3x-5y=15 $

Work Step by Step

(a.) The given point is $ (-5,-6) $ and the equation is $ 2x-y=-4 $. Substitute $ x=-5 $ and $ y=-6 $ into the equation. $ 2(-5)-(-6)=-4 $ $ -10+6=-4 $ $ -4 = -4 $. Satisfied. (b.) The given point is $ (-5,-6) $ and the equation is $ 3x-5y=15 $. Substitute $ x=-5 $ and $ y=-6 $ into the equation. $ 3(-5)-5(-6)=15 $ $ -15+30=15 $ $ 15 = 15 $. Satisfied.
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