Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 2 - Section 2.3 - The Algebra of Functions - Exercise Set: 16

Answer

$(f+g)(x)=4x^{2}-2$ $(f+g)(5)=98$

Work Step by Step

$(f+g)(x)=f(x)+g(x)$ $=4x^{2}-x-3+x+1$ $=4x^{2}-2$ Plugin $x=5$ into $4x^{2}-2$. $(f+g)(5)=4\times5^{2}-2=100-2=98$
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