#### Answer

$-5$

#### Work Step by Step

First, solving for x,
$13x-6=4(5x+2)$
$13x-6=20x+8$
$7x=-14$
$x=-2$
Second, solving for y,
$5-y=7(y+4)+1$
$5-y=7y+28+1$
$8y=-24$
$y=-3$
Now, inserting the values of x and y,
$x^{2}-(xy-y)=(-2)^{2}-((-2)(-3)-(-3))=4-(6+3)=-5$