## Intermediate Algebra for College Students (7th Edition)

a) (country, corruption rating) $$(Iceland, 9.7), (Finland, 9.6), (New\:Zealand,9.6), (Denmark, 9.5)$$ b) The relation in part $a$ is a function since the domain (countries) correspond to exactly one member of range (corruption rating). If we know the country, we can easily point out the corruption rating of that particular country. c) (corruption rating, country) $$(9.7,Iceland), (9.6, Finland), (9.6, New\:Zealand), (9.5, Denmark)$$ d) The relation in part $c$ is not a function since one the domains (corruption rating) correspond to two members of the range (countries) i.e. the member of the domain, 9.6, corresponds to both Finland and New Zealand. If we know the corruption rating of 9.6, we cannot easily identify the country to which this rating correspond.
a) (country, corruption rating) $$(Iceland, 9.7), (Finland, 9.6), (New\:Zealand,9.6), (Denmark, 9.5)$$ b) The relation in part $a$ is a function since the domain (countries) correspond to exactly one member of range (corruption rating). If we know the country, we can easily point out the corruption rating of that particular country. c) (corruption rating, country) $$(9.7,Iceland), (9.6, Finland), (9.6, New\:Zealand), (9.5, Denmark)$$ d) The relation in part $c$ is not a function since one the domains (corruption rating) correspond to two members of the range (countries) i.e. the member of the domain, 9.6, corresponds to both Finland and New Zealand. If we know the corruption rating of 9.6, we cannot easily identify the country to which this rating correspond.