Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 2 - Review Exercises - Page 172: 4

Answer

a) -5 b)16 c)-75 d)14a-5 e)7a+9

Work Step by Step

We substitute x for each value given a $f(0)=7*0-5=-5$ b $f(3)=7*3-5=16$ c $f(-10)=7*(-10)-5=-75$ d $f(2a)=7*2a-5=14a-5$ e $ f(a+2)=7*(a+2)-5=7a+14-5=7a+9$
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