Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 11 - Test - Page 871: 11



Work Step by Step

Write the decimal $0.\overline{73}$ as $0.73+0.0073+0.000073+...$ Thus, we have $S_{\infty}=\dfrac{a_1}{1-r}$ Here, $a_1=0.73,r=0.01$ Thus, $S_{\infty}=\dfrac{0.73}{1-0.01}=\dfrac{73}{99}$
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