Answer
$\dfrac{73}{99}$
Work Step by Step
Write the decimal $0.\overline{73}$ as $0.73+0.0073+0.000073+...$
Thus, we have $S_{\infty}=\dfrac{a_1}{1-r}$
Here, $a_1=0.73,r=0.01$
Thus, $S_{\infty}=\dfrac{0.73}{1-0.01}=\dfrac{73}{99}$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 11 - Test - Page 871: 11
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
