## Intermediate Algebra for College Students (7th Edition)

$\dfrac{73}{99}$
Write the decimal $0.\overline{73}$ as $0.73+0.0073+0.000073+...$ Thus, we have $S_{\infty}=\dfrac{a_1}{1-r}$ Here, $a_1=0.73,r=0.01$ Thus, $S_{\infty}=\dfrac{0.73}{1-0.01}=\dfrac{73}{99}$