Answer
The answer is $x=\frac{-1\pm\sqrt {33}}{4}$.
Work Step by Step
The given quadratic equation is
$2x^2=4-x$
Rearrange into standard form $ax^2+bx+c$.
$2x^2+x-4=0$
Where, $a=2,b=1$ and $c=-4$.
The solution of the standard form of the quadratic equation is
$x=\frac{-b\pm\sqrt {b^2-4ac}}{2a}$
Substitute all values.
$x=\frac{-1\pm\sqrt {1^2-4(2)(-4)}}{2(2)}$
$x=\frac{-1\pm\sqrt {1+32}}{4}$
$x=\frac{-1\pm\sqrt {33}}{4}$.
