Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 11 - Section 11.3 - Geometric Sequences and Series - Exercise Set - Page 857: 97

Answer

The answer is $\frac{1}{3}$.

Work Step by Step

First shaded part $=\frac{1}{4}$. Second shaded part $=\frac{1}{16}$. Third shaded part $=\frac{1}{64}$ and so on. This is the geometric sequence series. $\frac{1}{4},\frac{1}{16},\frac{1}{64},...$ infinite times. common ratio $=\frac{1}{4}$. The total part shaded of the largest square is. $=\frac{\frac{1}{4}}{1-\frac{1}{4}}$ $=\frac{\frac{1}{4}}{\frac{4-1}{4}}$ $=\frac{\frac{1}{4}}{\frac{3}{4}}$ $=\frac{1}{3}$.
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