Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 11 - Section 11.2 - Arithmetic Sequences - Exercise Set - Page 842: 90



Work Step by Step

As we know: $logm-log n=log\dfrac{m}{n}$ Thus, $log(\dfrac{x^2-25}{x+5})=3$ or, $log(\dfrac{x^2-25}{x+5})=3$ or, $log(x-5)=3$ or, $x-5=10^3 \implies x-5=1000$ or, $x=1005$
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