Answer
True
Work Step by Step
Standard form of an hyperbola is $\dfrac{x^2}{a^2}-\dfrac{y^2}{b^2}=1$
The statement is true because the graph of the equation $\dfrac{x^2}{9}-\dfrac{y^2}{4}=1$ defines a hyperbola whose transevrese axis is parallel to $x$-axis and the point on the graph of a hyperbola approaches to aysmptotes such as: $y=\pm \dfrac{b}{a}x=\pm \dfrac{2}{3}x$
