Answer
See below.
Work Step by Step
$f(x)=y=\pm\sqrt{4-x^2}\\y^2=4-x^2\\x^2+y^2=4\\\frac{x^2}{2^2}+\frac{y^2}{2^2}=1\\\frac{x^2}{4}+\frac{y^2}{4}=1$
This is the standard form of an ellipse, thus the original equation also defines an ellipse.
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 10 - Section 10.2 - The Ellipse - Exercise Set - Page 779: 59
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