Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 10 - Review Exercises - Page 819: 20

Answer

$\ln{(\sqrt[3] xy^7)}$

Work Step by Step

The product rule for logarithms says that $\log_b{MN}=\log_bM+\log_bN$ i.e. the logarithm of a product is the sum of the logarithms. The quotient rule for logarithms says that $\log_b{\frac{M}{N}}=\log_bM-\log_bN$ i.e. the logarithm of a quotient is the difference of the logarithms. The power rule for logarithms says that $\log_b{M^p}=p\log_bM$ i.e. the logarithm of a number with an exponent is the exponent times the logarithm of the number. $\log_ba=\frac{\log_ca}{\log_cb}$ Hence here: $\frac{1}{3}\ln x+7\ln y=\ln x^{\frac{1}{3}}+\ln y^7=\ln{(\sqrt[3] xy^7)}$
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