Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 10 - Review Exercises - Page 817: 30



Work Step by Step

Standard form of an hyperbola is $\dfrac{x^2}{a^2}-\dfrac{y^2}{b^2}=1$ In the given equation $-16x^2+36y^2-576=0$, it can be seen that the coefficients of $x^2$ and $y^2$ are having opposite sign . Thus, the graph of the given equation corresponds to an hyperbola.
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