Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Section 1.7 - Scientific Notation - Exercise Set - Page 91: 91

Answer

$$8.2 \times 10^{-16} + 4.3 \times 10^{-16}=1.25 \times 10^{-15}$$

Work Step by Step

$$8.2 \times 10^{-16} + 4.3 \times 10^{-16}$$ Since both expressions have the same value of exponents in 10, we can just proceed by adding the numerical values. Thus, $$8.2 \times 10^{-16} + 4.3 \times 10^{-16}$$ $$(8.2+4.3) \times 10^{-16}$$ $$= 12.5 \times 10^{-16}$$ Since numerical factors in scientific notation must be between 1 and 10, $12.5 \times 10^{-16}$ can be rewritten as: $$ 1.25 \times 10^{-15}$$
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