## Intermediate Algebra for College Students (7th Edition)

$$6x-5(4x+3)-10=-14x-25$$
$$6x-5(4x+3)-10$$ Expand $5(4x+3)$ = $(4x(5) + 3(5))$ $$=20x+15$$ Rewrite the equation: $$6x-(20x+15)-10$$ $$6x-20x-15-10$$ $$-14x-25$$