Answer
Values of y are $-5,0,3,4,3,0,-5$.
Work Step by Step
x can take value of integers from -3 to +3, i.e. -3,-2,-1,0,1,2,3.
We need to find y for above values of x.
Therefore,
For $x=-3, y=4-(-3)^{2}=4-9=-5$
For $x=-2, y=4-(-2)^{2}=4-4=0$
For $x=-1, y=4-(-1)^{2}=4-1=3$
For $x= \,\,\,\,0, y=4-(0)^{2}=4-0=4$
For $x=\,\,\,\,1, y=4-(1)^{2}=4-1=3$
For $x=\,\,\,\,2, y=4-(2)^{2}=4-4=0$
For $x=\,\,\,\,3, y=4-(3)^{2}=4-9=-5$
