## Intermediate Algebra for College Students (7th Edition)

The simplified value is $-7$.
$=\frac{9[4-(1+6)]-(3-9)^2}{5+\frac{12}{5-\frac{6}{2+1}}}$ Start from the lowest term of the denominator. $=\frac{9[4-(1+6)]-(3-9)^2}{5+\frac{12}{5-\frac{6}{3}}}$ $=\frac{9[4-(1+6)]-(3-9)^2}{5+\frac{12}{5-2}}$ $=\frac{9[4-(1+6)]-(3-9)^2}{5+\frac{12}{3}}$ $=\frac{9[4-(1+6)]-(3-9)^2}{5+4}$ $=\frac{9[4-(1+6)]-(3-9)^2}{9}$ Now solve the numrator by using BODMAS rule. $=\frac{9[4-7]-(3-9)^2}{9}$ $=\frac{9[-3]-(-6)^2}{9}$ $=\frac{-27-36}{9}$ $=\frac{-63}{9}$ $=-7$