Intermediate Algebra for College Students (7th Edition)

$\dfrac{1}{8}$
Recall, $a^{m}$ is equal to a multiplied by itself m times. Thus, we obtain: $-\left(-\frac{1}{2}\right)^3 \\=-(-\frac{1}{2})(-\frac{1}{2})(-\frac{1}{2}) \\=-(-\frac{1}{8}) \\=\frac{1}{8}$