## Intermediate Algebra for College Students (7th Edition)

The statement makes sense. No matter what values are substituted, the result will always be zero because the equation itself is equal to zero: $$2x^2y-2yx^2$$ can be rewritten to: $$2x^2y-2x^2y =0$$ which is actually equal to zero.
The statement makes sense. No matter what values are substituted, the result will always be zero because the equation itself is equal to zero: $$2x^2y-2yx^2$$ can be rewritten to: $$2x^2y-2x^2y =0$$ which is actually equal to zero.