## Intermediate Algebra for College Students (7th Edition)

Published by Pearson

# Chapter 1 - Section 1.1 - Algebraic Expressions, Real Numbers, and Interval Notation - Exercise Set - Page 14: 119

#### Answer

The statement makes sense. No matter what values are substituted, the result will always be zero because the equation itself is equal to zero: $$2x^2y-2yx^2$$ can be rewritten to: $$2x^2y-2x^2y =0$$ which is actually equal to zero.

#### Work Step by Step

The statement makes sense. No matter what values are substituted, the result will always be zero because the equation itself is equal to zero: $$2x^2y-2yx^2$$ can be rewritten to: $$2x^2y-2x^2y =0$$ which is actually equal to zero.

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