#### Answer

The statement makes sense. No matter what values are substituted, the result will always be zero because the equation itself is equal to zero:
$$2x^2y-2yx^2$$ can be rewritten to:
$$2x^2y-2x^2y =0$$ which is actually equal to zero.

Published by
Pearson

ISBN 10:
0-13417-894-7

ISBN 13:
978-0-13417-894-3

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