Answer
$(x+7)^{2}+(y-4)^{2}=64$
Work Step by Step
The standard equation for a circle with centre $(h,k)$ and radius $r$ is given by $(x-h)^{2}+(y-k)^{2}=r^{2}$
Given $(h,k)=(-7,4)$ and $r=8$.
$\implies (x-(-7))^{2}+(y-4)^{2}=8^{2}$
The equation of the given circle is
$(x+7)^{2}+(y-4)^{2}=64$
