Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 9 - Conic Sections, Sequences, and Series - 9.4 Geometric Sequences - 9.4 Exercises - Page 736: 9

Answer

Geometric with ratio $r=-3$

Work Step by Step

$4, -12, 36, -108, 324, -972, . . . $ $\frac{a_2}{a_1}=\frac{-12}{4}=-3=r$ $ra_2=-3\times(-12)=36=a_3$ $ra_3=-3\times(36)=-108=a_4$ $ra_4=-3\times(-108)=324=a_5$ and so on. The sequence is geometric with common ratio $r=-3$.
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