Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 9 - Conic Sections, Sequences, and Series - 9.1 Parabolas and Circles - 9.1 Exercises: 6

Answer

$a=-\frac{1}{4}$ and so the parabola opens left $h=23$ and $k=10$ and so the vertex is $(23,10)$. Since the parabola opens left, the axis of symmetry is $y=10$.

Work Step by Step

$x=-\frac{1}{4}y^2+5y-2$ $x=-\frac{1}{4}(y^2-20+8)$ $x=-\frac{1}{4}((y-10)^2-100+8)$ $x=-\frac{1}{4}(y-10)^2+23$ $a=-\frac{1}{4}$ and so the parabola opens left $h=23$ and $k=10$ and so the vertex is $(23,10)$. Since the parabola opens left, the axis of symmetry is $y=10$.
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