## Intermediate Algebra: Connecting Concepts through Application

$a=-\frac{1}{4}$ and so the parabola opens left $h=23$ and $k=10$ and so the vertex is $(23,10)$. Since the parabola opens left, the axis of symmetry is $y=10$.
$x=-\frac{1}{4}y^2+5y-2$ $x=-\frac{1}{4}(y^2-20+8)$ $x=-\frac{1}{4}((y-10)^2-100+8)$ $x=-\frac{1}{4}(y-10)^2+23$ $a=-\frac{1}{4}$ and so the parabola opens left $h=23$ and $k=10$ and so the vertex is $(23,10)$. Since the parabola opens left, the axis of symmetry is $y=10$.