Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 7 - Rational Functions - Chapter Review Exercises - Page 607: 16

Answer

$\frac{3p + 2}{p + 9}$

Work Step by Step

Factor the numerator by splitting the middle term: $6p^2 + 21p + 4p + 14$ Group the first two terms and the last two terms: $(6p^2 + 21p) + (4p + 14)$ Factor out common terms within the groups: $3p(2p + 7) + 2(2p + 7)$ Group the factors together: $(3p + 2)(2p + 7)$ Now, we can factor the denominator by splitting the middle term: $2p^2 + 18p + 7p + 63$ Group the first two terms and the last two terms: $(2p^2 + 18p) + (7p + 63)$ Factor out common terms within the groups: $2p(p + 9) + 7(p + 9)$ Group the factors together: $(2p + 7)(p + 9)$ Put the factored expressions into a fraction: $\frac{(3p + 2)(2p + 7)}{(2p + 7)(p + 9)}$ Cancel out common factors in the numerator and denominator: $\frac{3p + 2}{p + 9}$
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