Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 7 - Rational Functions - Chapter Review Exercises - Page 606: 8

Answer

The domain of this function is all real numbers except $-5$ and $3$.

Work Step by Step

To find the domain of this function, we need to find which values are excluded for $x$. In a rational function, the denominator cannot equal $0$ because the function would be undefined. Therefore, we need to set the denominator equal to $0$ and solve for $x$: $(x + 5)(x - 3) = 0$ According to the zero product property, if the product of two factors equals $0$, then either factor can be $0$; therefore, we can set each of these factors equal to $0$ and solve: $x + 5 = 0$ or $x - 3 = 0$ Add or subtract to solve: $x = -5$ or $x = 3$ These are the numbers $x$ cannot be. Therefore, the domain of this function is all real numbers except $-5$ and $3$.
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