Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 7 - Rational Functions - 7.4 Adding and Subtracting Rational Expressions - 7.4 Exercises - Page 588: 10

Answer

$\text{LCM}= m-6$.

Work Step by Step

Given \begin{equation} \frac{2 m}{m-6}, \quad \frac{7 m}{6-m}. \end{equation} Note that the second fraction can be rewritten as: \begin{equation} \begin{aligned} \frac{7 m}{6-m}&=\frac{7m}{-(m-6)} \\ &=\frac{-7m}{m-6}. \end{aligned} \end{equation} The two fractions now have the same denominator. Hence, the $\text{LCM}= m-6$.
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