Answer
$(H^+)=2.5\times 10^{-6}$ M
Work Step by Step
$pH=5.6$
Putting in the equation:
$pH=-\log(H^+)$
$5.6=-\log(H^+)$
$(H^+)=10^{-5.6}$
$(H^+)=10^{0.4}\cdot 10^{-6}$
$(H^+)=2.5\times 10^{-6}$ M
Intermediate Algebra: Connecting Concepts through Application
by Clark, Mark; Anfinson, Cynthia
Published by
Brooks Cole
ISBN 10:
0-53449-636-9
ISBN 13:
978-0-53449-636-4
Chapter 6 - Logarithmic Functions - Chapter Review Exercises - Page 543: 45
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