Answer
$x = ±2$
Work Step by Step
$2^{x^{2}+6} = 1024$
$2^{x^{2}+6} = 2^{10}$
$x^{2} + 6 = 10$
$x^{2} = 10 - 6$
$x^{2} = 4$
$x = ±\sqrt 4$
$x = ±2$
Intermediate Algebra: Connecting Concepts through Application
by Clark, Mark; Anfinson, Cynthia
Published by
Brooks Cole
ISBN 10:
0-53449-636-9
ISBN 13:
978-0-53449-636-4
Chapter 6 - Logarithmic Functions - 6.5 Solving Exponential Equations - 6.5 Exercises - Page 527: 41
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