Answer
Student did not use the product
property for logarithm correctly.
Work Step by Step
$\log x+\log y$
Using$\quad \log A+\log B=\log A B$
$\therefore \log x+\log y=\log x y$
$\log x y \neq \log x \log y$
$\therefore \log x+\log y \neq \log x \log y$
Student did not use product
property for logarithm correctly.