## Intermediate Algebra: Connecting Concepts through Application

a) $6250$ people b) $3$ days
a) $C(d) = 2(5^{d})$ $C(d) = 2(5^{5})$ $= 2(3125)$ $= 6250$ people b) $250 = 2(5^{d})$ $125 = 5^{d}$ $5^{3} = 5^{d}$ $d = 3$ days