## Intermediate Algebra: Connecting Concepts through Application

$x=6-\sqrt 3,6+\sqrt 3$
When taking the square root of a number, you get a positive and a negative answer. $-5(x-6)^2-15=-30$ $-5(x-6)^2=-15$ $(x-6)^2=3$ $x-6=\sqrt 3$ $x=6+\sqrt 3$ or $x-6=-\sqrt 3$ $x=6-\sqrt 3$. So $x=6-\sqrt 3,6+\sqrt 3$.