Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 4 - Quadratic Functions - 4.3 Finding Quadratic Models - 4.3 Exercises - Page 330: 1

Answer

$f(x) = 2(x+5)^2-15$

Work Step by Step

Start by graphing the data and the functions in the same figure window. $$\begin{aligned} f(x) &= 1.5(x+5)^2-15 \ ,\ a= 1.5\\ f(x) &= 1.8(x+5)^2-15\ ,\ a= 1.8\\ f(x) &= 2.0(x+5)^2-15\ ,\ a= 2.0\\ f(x) &= 2.3(x+5)^2-15\ ,\ a= 2.3\\ \end{aligned}$$ The graph shows that the parabola that best fit the data is $$f(x) = 2(x+5)^2-15.$$
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