Answer
Domain: The set of all real numbers.
Range: $[-58 , \infty )$
Work Step by Step
$$\begin{aligned}
f(x) &= 5(x+4)^2 -58.
\end{aligned}$$ Compare the given parabola with the standard vertex form:
$$ f(x) = a(x-h)^2+k.$$ We see that this parabola opens upward since the constant, $a= 5$ is positive. The minimum value is $k= -58$. The domain and range of the function are given below.
Domain: The set of all real numbers.
Range: $[-58 , \infty )$
