Answer
A) No horizontal intercept
B) One vertical intercept
Work Step by Step
This question is asking us to design a parabola with vertex at $(0,5)$. Start with the vertex form of a parabola and set $h= 0$ and $k= 5$. $$\begin{aligned}
f(x) &= a(x-h)^2+ k=a(x-0)^2+5=ax^2+5.
\end{aligned}$$ Since the parabola opens upward, the value of the constant $ a$ must be positive. For $a= 4$, we have. $$\begin{aligned}
y &= 4x^2+5.
\end{aligned}$$ A) The graph has no horizontal intercept.
B) It has one vertical intercept.
