## Intermediate Algebra: Connecting Concepts through Application

$(3m-4)^2$
$\bf{\text{Solution Outline:}}$ To factor the given expression, $9m^2-24m+16 ,$ find two numbers whose product is $ac$ and whose sum is $b$ in the quadratic expression $ax^2+bx+c.$ Use these $2$ numbers to decompose the middle term of the given quadratic expression and then use factoring by grouping. $\bf{\text{Solution Details:}}$ Using factoring of trinomials, the value of $ac$ in the trinomial expression above is $9(16)=144$ and the value of $b$ is $-24 .$ The $2$ numbers that have a product of $ac$ and a sum of $b$ are $\left\{ -12,-12 \right\}.$ Using these $2$ numbers to decompose the middle term of the trinomial expression above results to \begin{array}{l}\require{cancel} 9m^2-12m-12m+16 .\end{array} Grouping the first and second terms and the third and fourth terms, the given expression is equivalent to \begin{array}{l}\require{cancel} (9m^2-12m)-(12m-16) .\end{array} Factoring the $GCF$ in each group results to \begin{array}{l}\require{cancel} 3m(3m-4)-4(3m-4) .\end{array} Factoring the $GCF= (3m-4)$ of the entire expression above results to \begin{array}{l}\require{cancel} (3m-4)(3m-4) \\\\= (3m-4)^2 .\end{array}