#### Answer

$(4t-3)(t-10)$

#### Work Step by Step

$\bf{\text{Solution Outline:}}$
To factor the given expression, $
4t^2-43t+30
,$ find two numbers whose product is $ac$ and whose sum is $b$ in the quadratic expression $ax^2+bx+c.$ Use these $2$ numbers to decompose the middle term of the given quadratic expression and then use factoring by grouping.
$\bf{\text{Solution Details:}}$
Using factoring of trinomials, the value of $ac$ in the trinomial expression above is $
4(30)=120
$ and the value of $b$ is $
-43
.$ The $2$ numbers that have a product of $ac$ and a sum of $b$ are $\left\{
-3,-40
\right\}.$ Using these $2$ numbers to decompose the middle term of the trinomial expression above results to
\begin{array}{l}\require{cancel}
4t^2-3t-40t+30
.\end{array}
Grouping the first and second terms and the third and fourth terms, the given expression is equivalent to
\begin{array}{l}\require{cancel}
(4t^2-3t)-(40t-30)
.\end{array}
Factoring the $GCF$ in each group results to
\begin{array}{l}\require{cancel}
t(4t-3)-10(4t-3)
.\end{array}
Factoring the $GCF=
(4t-3)
$ of the entire expression above results to
\begin{array}{l}\require{cancel}
(4t-3)(t-10)
.\end{array}