Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 3 - Exponents, Polynomials and Functions - 3.4 Factoring Polynomials - 3.4 Exercises: 12

Answer

$= 6a^{2}bc(4ab - 3bc + 5)$

Work Step by Step

$24a^{3}b^{2}c - 18a^{2}b^{2}c^{2} +30a^{2}bc$ $= 6a^{2}bc(4ab - 3bc + 5)$
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