Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 3 - Exponents, Polynomials and Functions - 3.3 Composing Functions - 3.3 Exercises - Page 256: 3

Answer

$\text{a) } f(g(x))=-18x+35 \\\text{b) } g(f(x))=-18x-39$

Work Step by Step

$\bf{\text{Solution Outline:}}$ With \begin{array}{l}\require{cancel} f(x)= 3x+8 \\g(x)= -6x+9 ,\end{array} to find $ f(g(x)) ,$ replace $x$ with $g(x)$ in $f.$ To find $g(f(x)),$ replace $x$ with $f(x)$ in $g.$ $\bf{\text{Solution Details:}}$ Replacing $x$ with $g(x)$ in $f$, then \begin{array}{l}\require{cancel} f(g(x))=f(-6x+9) \\\\ f(g(x))=3(-6x+9)+8 \\\\ f(g(x))=-18x+27+8 \\\\ f(g(x))=-18x+35 .\end{array} Replacing $x$ with $f(x)$ in $g$, then \begin{array}{l}\require{cancel} g(f(x))=g(3x+8) \\\\ g(f(x))=-6(3x+8)+9 \\\\ g(f(x))=-18x-48+9 \\\\ g(f(x))=-18x-39 .\end{array} Hence, \begin{array}{l}\require{cancel} \text{a) } f(g(x))=-18x+35 \\\text{b) } g(f(x))=-18x-39 .\end{array}
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