#### Answer

x$\gt$$\frac{15}{7}$

#### Work Step by Step

5x+7$\lt$12x-8
7+8$\lt$12x-5x
15$\lt$7x
$\frac{15}{7}$$\lt$x
x$\gt$$\frac{15}{7}$

Published by
Brooks Cole

ISBN 10:
0-53449-636-9

ISBN 13:
978-0-53449-636-4

x$\gt$$\frac{15}{7}$

5x+7$\lt$12x-8
7+8$\lt$12x-5x
15$\lt$7x
$\frac{15}{7}$$\lt$x
x$\gt$$\frac{15}{7}$

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