## Intermediate Algebra: Connecting Concepts through Application

2w-5t=-1 2w=5t-1 w=2.5t-0.5 Substitute the equivalent of w in the other given equation. 3w-4t=2 2(2.5t-0.5)-4t=2 5t-1=2 5t=2+1 5t=3 t=$\frac{3}{5}$ t=0.6 Now that we have the answer for the t-value, plug it back into one of the original equations to find the answer for the w-value. w=2.5t-0.5 w=2.5(0.6)-0.5 w=1.5+0.5 w=2 Therefore the answer is (0.6, 2). There is only one solution so the system is consistent and the lines are independent.