#### Answer

$(3, 2)$

#### Work Step by Step

Add the equations together:
\begin{array}\\
x+4y=11\\
\underline{5x-4y=7}\\
6x+0y=18\\\\
\end{array}
Solve for $x$ to obtain:
\begin{align*}
6x&=18\\
x&=\frac{18}{6}\\
x&=3\end{align*}
Substitute $3$ to $x$ in the first equation to obtain:
\begin{align*}
x+4y&=11\\
3+4y&=11\\
4y&=11-3\\
4y&=8\\
y&=\frac{8}{4}\\
y&=2
\end{align*}
Check by substituting $3$ to $x$ and $2$ to $y$ in the second equation to obtain:
\begin{align*}
5(3)-4(2)&=7\\
15-8&=7\\
7&\stackrel{\checkmark}=7
\end{align*}
Therefore, the solution is $(3, 2)$.