Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 2 - Systems of Linear Equations and Inequalities - 2.2 Solving Systems of Equations Using the Substitution Method - 2.2 Exercises - Page 153: 43

Answer

No solution (inconsistent system)

Work Step by Step

Given: $$\begin{cases} y &= -2x+8\\ x+\frac{1}{2}y &=3. \end{cases}$$ First, rewrite the second equation in slope intercept form. $$\begin{aligned} x+\frac{1}{2}y &=3 \\ \frac{1}{2}y &= -x+3\\ 2\cdot\left(\frac{1}{2}y \right)&= 2\cdot\left(-x+3\right)\\ y&=-2x+6. \end{aligned}$$ Compare the two equations $$\begin{cases} y &= -2x+8\\ y &=-2x+6. \end{cases}$$ By comparison, we see that both lines have the same slopes but different y-intercept. This means that the lines are parallel and therefore inconsistent. There is no solution for the system. Tom's solution is the correct answer. However, the error in Matt's solution is seen here. He started by substituting for $y$ from the first equation into the second. $$\begin{aligned} x+\frac{1}{2}\left(-2x+8\right) &= 3\\ x-x+4&= 3\\ 4&=3 \end{aligned}$$ which is clearly false. He also claimed that the system is consistent with dependent lines with infinitely many solutions. All of these claims are clearly false.
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