## Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole

# Chapter 2 - Systems of Linear Equations and Inequalities - 2.2 Solving Systems of Equations Using the Substitution Method - 2.2 Exercises: 10

#### Answer

(-8, 0.6) consistent and independent

#### Work Step by Step

y=$\frac{1}{5}$x+$\frac{11}{5}$ y=0.2x+2.2 Plug the equivalent of y into the other given equation: y=$\frac{2}{5}$x+$\frac{19}{5}$ y=0.4x+3.8 (0.2x+2.2)=0.4x+3.8 2.2-3.8=0.4x-0.2x -1.6=0.2x -8=x x=-8. Now that we have the answer for the x-value, plug it back into one of the original equations to find the answer for the y-value: y=0.2x+2.2 y=0.2(-8)+2.2 y=-1.6+2.2 y=0.6. Therefore the solution is (-8, 0.6). Since there is only one solution, the system is consistent and the lines are independent.

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