Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 1 - Linear Functions - 1.5 Finding Equations of Lines - 1.5 Exercises - Page 75: 23

Answer

$y=181.5t+226.5$

Work Step by Step

Let $y$ be the number of teenagers who underwent gastric bypass surgery and $t$ be the number of years since $2000$. A linear equation for the number of teenagers having gastric bypass surgery $t$ years since $2000$ takes the form of $$ y=mt+b, $$ where $m$ is the slope and $b$ is the $y$-intercept. Since in $2001$ (i.e. $1$ year since $2000$) the number of teenagers who underwent gastric bypass surgery is $408$, this can be represented by the ordered pair $(t_1,y_1)=(1,408)$. Since in $2003$ (i.e. $3$ years since $2000$) the number of teenagers who underwent gastric bypass surgery is $771$, this can be represented by the ordered pair $(t_2,y_2)=(3,771)$. The formula for finding the slope, $m$, of the line passing through two points, $(t_1,y_1)$ and $(t_2,y_2)$ is given by $m=\frac{y_1-y_2}{t_1-t_2}$. That is, $$\begin{aligned} m&=\frac{y_1-y_2}{t_1-t_2} \\&= \frac{408-771}{1-3} \\&= \frac{-363}{-2} \\&= 181.5 .\end{aligned} $$With $m=181.5$, then the linear equation for the number of teenagers having gastric bypass surgery $t$ years since $2000$ takes the form of $$ y=181.5t+b .$$Since the line passes through the point $(1,408)$, substitute $t=1$ and $y=408$ in the equation above to solve for $b$. That is, $$\begin{aligned} y&=181.5t+b \\ 408&=181.5(1)+b \\ 408&=181.5+b \\ 408-181.5&=b \\ b&=226.5 .\end{aligned} $$With $b=226.5$, then the linear equation for the number of teenagers having gastric bypass surgery $t$ years since $2000$ takes the form of $$ y=181.5t+226.5 .$$
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