## Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole

# Chapter 1 - Linear Functions - 1.3 Fundamentals of Graphing and Slope - 1.3 Exercises - Page 50: 5

#### Answer

part a: $m=-5$ part b: decreasing part c: $(0,5)$ part d: $(1,0)$

#### Work Step by Step

part a: Formula for slope: $m=\frac{y_{2}-{y_{1}}}{x_{2}-{x_{1}}}$ Substitute: $m=\frac{{5}-{0}}{{0}-{1}}$ $\ast$You can choose any two given points on the graph for substituting, but this explanation is solved using $(1,0)$ and $(0,5)$. Simplify: $m=\frac{5}{-1}=-5$ part b: The slope is negative so the line is decreasing. part c: The vertical intercept is also known as the y-intercept. The line crosses through 5 on the y-axis. In proper form, the vertical intercept is $(0,5)$. part d: The horizontal intercept is also known as the x-intercept. The line crosses through 1 on the x-axis. In proper form, the horizontal intercept is $(1,0)$.

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